Solution to removeConsecutiveRepeatedCharacters

removeConsecutiveRepeatedCharacters(text):
    #  rcrc("bookkeeper")   should return "bokeper"
    #  rcrc("eeeecccchhhh") should return "ech"
    #  rcrc("eve")          should return "eve"

#-----------------------
# We'll be looking at pairs, i and i+1
# if the pair is the same, we're looking at consec. rep. chars and can ignore them
# if it's different, then we're encountering that second character for the first time,
# and should make sure to record it now
# With this method, we must be very careful about our ranges and off by 1 errors 

def rcrc1(text):
    result = ""
    for i in range(len(text)-1):
        if text[i] != text[i+1]: # if not duplicate, i.e. "ok", should record the k
            result += text[i+1] #record the next char, since it's new
        # else, it's a duplicate like "oo", so we've already added it before
    
    #we never added text[0], add it now
    return text[0] + result;

#-----------------------
# This second method requires us to remember what the last
# character was, but now we don't have to think about pairs
# or index out of range errors.
# However, we must be careful to be consistent with updating lastSeenChar each time

def rcrc2(text):
    result = ""
    lastSeenChar = "" #first time, we haven't seen a char

    for i in range(len(text)):
        if text[i] != lastSeenChar: #found a non-duplicate
            result += text[i]
        #Then, update lastSeenChar so it stays up-to-date
        lastSeenChar = text[i]
    return result